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Recall the cyclic bicomplex
which after passing to total complex gives a complex computing
cyclic homology of an algebra. There is an obvious way to extend
this bicomplex to the right using the same differentials
Furthermore we can repeat each row going down continuing the same pattern.
![\begin{displaymath}
\xymatrix{
& \vdots \ar[d] & \vdots \ar[d] & \vdots \ar[d] &...
...[l] \ar[d] & C_0 \ar[l]_B \\
\hdots & C_0 \ar[l] \\
\hdots
}
\end{displaymath}](img382.png) |
(3) |
This is called a periodic bicomplex. If the columns of the cyclic bicomplex we started with
were indexed by natural numbers starting from 0, then in the periodic bicomplex
(
) we have columns indexed by integers.
To work with the total complex of the periodic bicomplex one should use
the product instead of a sum. Otherwise one would get zero in the homology.
Pawel Witkowski
2006-11-07