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Periodic and negative cyclic homology

Recall the cyclic bicomplex

\begin{displaymath}
\xymatrix{
\vdots \ar[d] & \vdots \ar[d] &\vdots \ar[d] & \v...
...[l]_B & C_0 \ar[l]_B \\
C_1 \ar[d]_b & C_0 \ar[l]_B \\
C_0
}
\end{displaymath}

which after passing to total complex gives a complex computing cyclic homology of an algebra. There is an obvious way to extend this bicomplex to the right using the same differentials

\begin{displaymath}
\xymatrix{
& \vdots \ar[d] & \vdots \ar[d] & \vdots \ar[d] &...
...ar[l]_B& C_0 \ar[l]_B \\
\hdots & C_1 \ar[l] & C_0 \ar[l]_B
}
\end{displaymath}

Furthermore we can repeat each row going down continuing the same pattern.
\begin{displaymath}
\xymatrix{
& \vdots \ar[d] & \vdots \ar[d] & \vdots \ar[d] &...
...[l] \ar[d] & C_0 \ar[l]_B \\
\hdots & C_0 \ar[l] \\
\hdots
}
\end{displaymath} (3)

This is called a periodic bicomplex. If the columns of the cyclic bicomplex we started with were indexed by natural numbers starting from 0, then in the periodic bicomplex ([*]) we have columns indexed by integers.

To work with the total complex of the periodic bicomplex one should use the product instead of a sum. Otherwise one would get zero in the homology.
\begin{defn}
% latex2html id marker 2404The cohomology of the total complex of...
...(n+1)}$,
then we denote this homology by $\HN_*(A)$\ or $\HC^-_*(A)$.
\end{defn}



Pawel Witkowski 2006-11-07