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Coisotropic creed

When $A_{\hbar}$ is a quantization of $(M, \Pi)$ then one-sided ideals in $A_{\hbar}$ should correspond to coisotropic submanifolds. The motivation for this comes from characterization

\begin{displaymath}
\xymatrix{
{\begin{array}{l}
\text{Poisson submanifold } N
\...
...NGER THAN} \\
\text{BEING A SUBALGEBRA}
\end{array}} \ar[l]
}
\end{displaymath}


\begin{prop}
Let $A_{\hbar}$\ is a quantization of $M$. Take $I$\ to be a right ...
..._0=I/\hbar I$\ is an ideal in $A_0$\ and a Poisson subalgebra in $M$.
\end{prop}

\begin{proof}
Let $i\in I$, $f\in A_{\hbar}$
\begin{displaymath}
f*i = fi + \hba...
...ss{i}{j}\in I_0
\end{displaymath}so $I_0$\ is a Poisson subalgebra.
\end{proof}
We will stick to this creed and declare the following
\begin{defn}
Let $A$\ be (*)-Hopf algebra. A \textbf{right (real) coisotropic qu...
...ed with an involution $\sg$
such that $p\circ(*\circ S)=\sg\circ p$).
\end{defn}

\begin{prop}
$C$\ is a right (real) coisotropic quantum subgroup if and only if
...
... such that
\begin{displaymath}
p\: A\to A/I_C\cong C
\end{displaymath}\end{prop}

\begin{remark}
All Poisson subgroups can be quantized in a context of functorial...
...in such context
whether all coisotropic subgroups can be quantized.
\end{remark}

\begin{prop}
\mbox{}
\begin{enumerate}
\item Let $C$\ be a coisotropic quantum s...
...laymath}is a right ideal and two sided coideal of $A$.
\end{enumerate}\end{prop}
Is this

\begin{displaymath}
\xymatrix{
{\begin{array}{l}
\text{coisotropic quantum}\\
\...
...e quantum}\\
\text{homogeneous spaces} \ar[l]
\end{array}}
}
\end{displaymath}

a bijective correspondence ? Is it true that quotient by quantum subgroups are characterized by $S^2$-invariance ? Almost.

Let $B$ be a right coideal subalgebra. Take

\begin{displaymath}
AB^+:= B\cap \ker\eps = \{ b-\eps(b)1 : b\in B\}
\end{displaymath}

In general $B\subseteq A^{\mathrm{co} A/AB^+}$ but not necessarily equal. If the antipode is bijective and we restrict to left faithfully flat right coideal subalgebras and left faithfully coflat coisotropic quantum subgroups, then in that case $S^2$-invariance corresponds to quotient by a coisotropic quantum subgroup.



Pawel Witkowski 2006-06-26