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Periodicity

Write $\Cl_{pq} := \Cl(\bR^{p+q}, g)$, where $g$ has signature $(p, q)$, and the orthonormal basis is written as $\{e_1,\dots, e_p, \eps_1, \dots, \eps_q\}$, where $e_1^2 =\cdots= e_p^2 = 1$ and $\eps_1^2 =\cdots= \eps_q^2 = -1$. For example,
\begin{align*}
\Cl_{10} &= \bR \oplus \bR ;
\\
\Cl_{01} &= \bC, \words{with} \e...
...2} &= \bH, \words{with}
\eps_1 = i, \eps_2 = j, \eps_1\eps_2 = k.
\end{align*}


\begin{lem}[\lq\lq (1,1)-periodicity'']
$\Cl_{p+1, q+1} \isom \Cl_{pq} \ox M_2(\bR)$.
\end{lem}


\begin{proof}
Take $V = \bR^{p+q+2}$, $A = \Cl_{pq}\ox M_2(\bR)$. Define
$f\: V...
...
It is an isomorphism, because the dimensions over $\bR$ are equal.
\end{proof}


\begin{lem}
$\Cl^0_{p+1, q} \isom \Cl_{qp}$.
\end{lem}


\begin{proof}
Define $f\: \bR^{q+p} \to \Cl^0_{p+1, q}$ on basic vectors by
\b...
...icommute. The rest of the proof is
like that of the previous Lemma.
\end{proof}


\begin{lem}
$\Cl_{p+4, q} \isom \Cl_{pq} \ox M_2(\bH) \isom \Cl_{p, q+4}$.
\end{lem}


\begin{proof}
We will prove the first isomorphism. Take $A = \Cl_{pq} \ox M_2(\b...
...atrix}1 & 0 \ 0 & -1 \end{pmatrix}.
\tag*{\qed}
\end{align}\hideqed
\end{proof}


\begin{cor}[\lq\lq (+8)-periodicity'']
$\Cl_{p+8, q} \isom \Cl_{pq} \ox M_{16}(\bR) \isom \Cl_{p, q+8}$.
\end{cor}

\begin{proof}
This reduces to $M_2(\bH) \ox_\bR M_2(\bH) \isom M_{16}(\bR)$, tha...
...s to $\bH \ox_\bR \bH \isom M_4(\bR)$, which is left as an exercise.
\end{proof}

All $\Cl_{pq}$ are given, up to $M_N(\bR)$ tensor factors, by $\Cl_{p0}$ for $p = 1,\dots,8$:
\begin{align}
\Cl_{10} &= \bR \oplus \bR \notag \\
\Cl_{20} &= M_2(\bR) \notag ...
... \notag \\
\Cl_{70} &= M_8(\bC) \notag \\
\Cl_{80} &= M_{16}(\bR)
\end{align}
Two algebras $\Cl_{10}$ and $\Cl_{50}$ are direct sums of simple algebras, and the others are simple. We could also define $\Cl_{00} = \bR$ (the base field), so that Corollary [*] holds even when $p = q = 0$.

Those eight algebras $\Cl_{p0}$ can be arranged on a ``spinorial clock'', which is taken from Budinich and Trautman's book [BT].


\begin{diagram}[small]
&& && \bC && && \\
&& &\ldTo^{6}& &\luTo^{7}& && \\
&& ...
...&& && \bR && \\
&& &\rdTo_{3}& &\ruTo_{2}& && \\
&& && \bC && &&
\end{diagram}

If $p - q \equiv m \bmod 8$, then $\Cl_{pq}$ is of the form $A \ox M_N(\bR)$, where $A$ is the diagram entry at the head of the arrow labelled $m$. Moreover, Lemma [*] says that the even subalgebra $\Cl^0_{pq}$ is of the same kind, where $A$ is now the diagram entry at the tail of the arrow labelled $m$. The matrix size $N$ is easily determined from the real dimension, in each case. In this way, the spinorial clock displays the full classification of real Clifford algebras.


next up previous contents
Next: Chirality Up: Clifford algebras and spinor Previous: The trace   Contents
Pawel Witkowski 2006-03-14