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Symmetry of the Dirac operator

We now regard $\Dslash$ as an operator on $L^2(M, S)$, defined initially on the dense domain $\sS = \Ga_\smooth(M, S)$.


\begin{prop}
$\Dslash$ is \emph{symmetric}: that is, whenever $\phi, \psi \in \...
...ket{\Dslash\phi}{\psi} = \braket{\phi}{\Dslash\psi}.
\end{displaymath}\end{prop}


\begin{proof}
We compute the pairings $\pairing{\Dslash\phi}{\psi}$ and
$\pairi...
...si}
= -i\divg Z_{\phi\psi}
\end{displaymath}which has integral zero.
\end{proof}



Pawel Witkowski 2006-03-14